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Find the nth partial sum of the arithmetic sequence for the given value of n.

a)

6, 19, 32, 45, …, n = 60

b) -8, -3, 2, 7, …, n = 120

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02:21

Find the $n$ th partial sum of the arithmetic sequence for the given value of $n$.$$0,-9,-18,-27, \dots, n=40$$

01:21

Find the $n$th partial sum of the arithmetic sequence.$$a_{n}=6 n ; n=12$$

01:30

Find the $n$th partial sum of the arithmetic sequence.$$a_{n}=1-2 n ; n=20$$

00:59

Find an explicit rule for the nth term of the arithmeticsequence.-20, -14, -8, -2, …A. an = -20 + 6(n+2)B. an = -20 + 6(n-1)C. an = -20 × 6(n-1)D. an = -20 + 6(n+1)

Transcript

Hay student welcome to the solution for an arithmetic sequence. Some of the first in terms would be equal to n over 2 multiplied by twice the first term, plus n minus 1 multiplied by d. In the a part of the question we have. The first term is 6 and common difference is 13 point n equals 60 point. So s n would be equal to 60 divided by 2 multiplied by twice 6 plus 59…

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