SOLVED: Express the area of the shaded region in terms of (a) an integral with respect to x and (b) an integral with respect to y. You do not need to evaluate the integrals. Given: y = x^3, y = √x E

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Express the area of the shaded region in terms of (a) an integral with respect to x and (b) an integral with respect to y. You do not need to evaluate the integrals.
Given: y = x^3, y = √x
Express the shaded region as an integral with respect to x:
A = ∫(√x – x) dx
Express the shaded region as an integral with respect to y:
A = ∫dy

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Express the area of the shaded region in terms of (a) an integral with respect to X and (b) an integral with respect to y: You do not need to evaluate the integrals.
Express the shaded region as an integral with respect to x
dx
Express the shaded region as an integral with respect to y:
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Set up an integral for the area of the shaded region: Evaluate the integral to find the area of the shaded region
X= y -4Y
(-3,3)
<=?y-y
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Express the area of the following shaded regions in terms of (a) one or more integrals with respect to $x,$ and
(b) one or more integrals with respect to $y .$ You do not need to evaluate the integrals.
(FIGURE CANNOT COPY)
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Transcript

In this question, from the graph, the area of the region with respect to x, y is equal to root x, y is equal to x cube, root x is equal to 7 cube, here x cube, then x is equal to x raised to power 6. So x, x raised to power 5 minus 1 which is equal to 0, the value of x is 0 and 1. When x is equal to 0, y is equal to 0, when x is equal to 1, y is equal to 1. Therefore, the point of the vertex R, point of intersect R, 0, 0.…

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You are watching: SOLVED: Express the area of the shaded region in terms of (a) an integral with respect to x and (b) an integral with respect to y. You do not need to evaluate the integrals. Given: y = x^3, y = √x E. Info created by THVinhTuy selection and synthesis along with other related topics.

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