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Consider the following Y =x2 Y = 12 _ X

Find the area of the region by integrating with respect to

(b) Find the area of the region by integrating with respect to y

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03:57

Consider the following:y = x^2y = 6 – x

(a) Find the area of the region by integrating with respect to x.(b) Find the area of the region by integrating with respect to y.

05:22

Find the area of the region by integrating (a) with respect to $x$ and (b) with respect to $y$.$$\begin{aligned}&y=x^{2} \\&y=6-x\end{aligned}$$

03:15

Set up the integral and find the area of the region bounded by equations by integrating with respect to x and with respect to y. y= x^2y= 12-x

07:09

Find the area of the region by integrating (a) with respect to $x$ and (b) with respect to $y$.$$\begin{aligned}&x=4-y^{2} \\&x=y-2\end{aligned}$$

02:56

Sketch the region enclosed by the given curves and find itsarea. Decide whether to integrate with respect to x or yy = 12 − x^2 , y = x^2 − 6

Transcript

We have here exponent equation, which is 13 to the power of 25 added by 4 to the power of 81 added by 5 to the power 411 o. These are the given parts and we have to find here the unit digit unit digit of the sun. So now, in the solution of this question, first of all, as we can see, an exponent of power, 13 and exponent of power 13 repeats its union digiti digit after the 4 times 4 cars. So this will be as 4 repeats after 2 place and for this is for 4 place for 13, and for then this is for 13 and secondly, we have for 44 repeats after 2 places and similarly pi repeats at the unit. Dis after asunder will be 5. Always fine so each time always their 5. Alas, so now in solution of this question for 13 to the power of 25 point,…

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