# Pythagoras theorem

How to determine the hypotenuse, opposite, and adjacent legs of a triangle
How to determine the hypotenuse, opposite, and adjacent legs of a triangle

One to one maths interventions built for KS4 success

Weekly online one to one GCSE maths revision lessons now available

In order to access this I need to be confident with:

Substitution Squares and square roots Solving equations Rounding numbers

This topic is relevant for:

Here we will learn about Pythagoras theorem, including how to find sides of a right-angled triangle and how to use Pythagoras theorem to check if a triangle has a right angle or not.

There are also Pythagoras theorem worksheets based on Edexcel, AQA and OCR exam questions, along with further guidance on where to go next if you’re still stuck.

Pythagoras theorem states that the square of the longest side of a right angled triangle (called the hypotenuse) is equal to the sum of the squares of the other two sides.

Pythagoras theorem is:

Side c is known as the hypotenuse, which is the longest side of a right-angled triangle and is opposite the right angle.
Side a and side b are known as the adjacent sides because they are adjacent (next to) the right angle.

If we know any two sides of a right angled triangle, we can use Pythagoras theorem to work out the length of the third side.

We can only use Pythagoras theorem with right-angled triangles.

E.g.
Let’s look at this right-angled triangle:

We can see that three squares have been drawn next to each of the sides of the triangle.
The area of the square with side length 3 = 3 \times 3=3^2=9
The area of the square with side length 4 = 4\times 4=4^2=16
The area of the square with side length 5 = 5\times5=5^2=25

We can see that when we add together the areas of the squares on the two shorter sides we get the area of the square on the longest side.

We can see that when we square the lengths of the two shorter sides of a right angled triangle and add them together, we get the square of the longest side.

3, 4, 5 is known as a Pythagorean triple.
There are other Pythagorean triples such as 5, 12, 13 and 8, 15, 17 .

In order to use Pythagoras theorem:

Get your free pythagoras theorem worksheet of 20+ questions and answers. Includes reasoning and applied questions.

Get your free pythagoras theorem worksheet of 20+ questions and answers. Includes reasoning and applied questions.

It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

2Write down the formula and apply the numbers.

Make sure you give your final answer in the correct form including units where appropriate.

x = 8.54 cm to 2 decimal places

An alternative method is to rearrange the formula and put the entire calculation into a calculator.

Label the sides of the triangle.

It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

Write down the formula and apply the numbers.

Make sure you give your final answer in the correct form including units where appropriate.

x = 11.4 cm to 3 significant figures

An alternative method is to rearrange the formula and put one calculation into a calculator.

Label the sides of the triangle.

It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

We will label the short side we are trying to find as side a .

Write down the formula and apply the numbers.

Make sure you give your final answer in the correct form; including units where appropriate.

x = 6.24 cm to 2 significant figures

An alternative method is to rearrange the formula and put one calculation into a calculator.

Label the sides of the triangle.

It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

We will label the short side we are trying to find as side a .

Write down the formula and apply the numbers.

Make sure you give your final answer in the correct form; including units where appropriate.

x = 16.7 cm to 3 significant figures

An alternative method is to rearrange the formula and put one calculation into a calculator.

Is the triangle below a right-angled triangle?

Label the sides of the triangle.

If the triangle is a right-angled triangle, then Pythagoras theorem should work:
It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

Write down the formula and apply the numbers.

Pythagoras theorem only works with right-angled triangles.

So because,

The sides of the triangles do not fit with Pythagoras theorem. Therefore the triangle is NOT a right-angled triangle.

Is the triangle below a right-angled triangle?

Label the sides of the triangle.

If the triangle is a right-angled triangle, then Pythagoras theorem should work:

It is very important to label the hypotenuse (the longest side) correctly with c . The adjacent sides, next to the right angle can be labelled a and b either way around as they are interchangeable.

Write down the formula and apply the numbers.

This is correct.

Pythagoras theorem only works with right-angled triangles.
So because,

The sides of the triangles fit with Pythagoras theorem. Therefore the triangle is a right-angled triangle.

It is very important to make sure that the hypotenuse is correctly identified and labelled c . You can find the hypotenuse by identifying the side which is opposite the right angle.

The triangles can be drawn in different orientations.
E.g.

Lengths can be decimals, fractions or even irrational numbers such as surds,

E.g.
\sqrt{2} .

Pythagoras theorem only works on right-angle triangles, however we can sometimes calculate the lengths of other triangles by splitting them into right angled triangles.
E.g.
An isosceles triangle can be made into 2 right-angled triangles by putting in the line of symmetry.

An application of Pythagoras theorem is to extend it to work on other shapes such as a trapezium.

If you need to use Pythagoras theorem in a question with multiple steps, do not round until the very end of the question or you will lose accuracy. For example, you may need to find the height of a triangle, and then use that height to find its area.

\begin{aligned} a^2 + b^2 &= c^2 \\\\ 7^2 + 5^2 &= x^2 \\\\ x^2 &= 7^2 + 5^2\\\\ x^2 &= 49+25 \\\\ x^2 &= 74\\\\ x &= \sqrt{74}\\\\ x &= 8.602325… \end{aligned}

x=8.60 cm to 2 decimal places

\begin{aligned} a^2 + b^2 &= c^2 \\\\ 14^2 + 10^2 &= x^2\\\\ x^2 &= 14^2 + 10^2\\\\ x^2 &= 196+10\\\\ x^2 &= 296\\\\ x &= \sqrt{296}\\\\ x &= 17.20465… \end{aligned}

x=17.2 cm to 1 decimal place.

\begin{aligned} a^2 + b^2 &= c^2 \\\\ x^2 + 10^2 &= 18^2\\\\ x^2+100 &= 324 \\\\ x^2 &= 324 – 100 \\\\ x^2 &= 224\\\\ x &=\sqrt{224}\\\\ x &= 14.96662… \end{aligned}

x=14.97 cm to 2 decimal places

\begin{aligned} a^2 + b^2 &= c^2 \\\\ x^2 + 2.5^2 &= 7.2^2\\\\ x^2+6.25 &= 51.84 \\\\ x^2 &= 51.84 – 6.25 \\\\ x^2 &= 45.59\\\\ x &=\sqrt{45.59}\\\\ x &= 6.75203… \end{aligned}

x=6.75 cm to 2 decimal places

5. Is this triangle a right-angled triangle? Give a reason for you answer:

No because I measured the angle and it was not 90^{\circ}

No because 12^2+5^2 ≠ 13^2

Yes because I measured the angle and it was 90^{\circ}

Yes because 12^2+5^2=13^2

\begin{aligned} a^2 + b^2 &= c^2 \\\\ 12^2 + 5^2 &= 13^2\\\\ 144+25 &= 169 \\\\ 169 &= 169 \end{aligned}

This is correct. Pythagoras’ theorem only works with right-angled triangles.

Therefore the triangle is a right-angled triangle.

6. Is this triangle a right-angled triangle? Give a reason for you answer:

Yes because 6^2+13^2=14^2

No because 6^2+13^2 ≠ 14^2

Yes because I measured the angle and it was 90^{\circ}

No because I measured the angle and it was not 90^{\circ}

\begin{aligned} a^2 + b^2 &= c^2 \\\\ 6^2 + 13^2 &= 14^2\\\\ 36+169 &= 196 \\\\ 205 &= 169 \end{aligned}

This is NOT correct. Pythagoras’ theorem only works with right-angled triangles.

Therefore the triangle is NOT a right-angled triangle.

1. ABC is a right-angled triangle.

Calculate the length of AC.

(3 marks)

(1)

\sqrt{214.58}

(1)

AC = 14.6485… = 14.6 cm

(1)

2. Triangle ABC has a perimeter of 19 cm.

AB = 5 cm \\ BC = 6 cm

By calculation, deduce whether triangle ABC is a right-angled triangle.

(4 marks)

Third side is 8 cm and is the longest so it is the hypotenuse

(1)

5^2 + 6 ^2 = 61

(1)

\sqrt{61}=7.81…

OR

8^2=64

(1)

Triangle ABC is NOT a right-angled triangle

(1)

3. A frame is made from wire

The frame is in the shape of a rectangle 10 cm by 15 cm.

The diagonal of the rectangle is also made from wire.

Calculate the total length of wire needed to make the frame and the diagonals.

(4 marks)

(1)

\sqrt{325}=18.02775

(1)

18.02775.. + (2\times 15) + (2\times 10)

(1)

68.027756…. = 68.0 cm

(1)

Pythagoras theorem is named after a Greek mathematician who lived about

You have now learned how to:

Prepare your KS4 students for maths GCSEs success with Third Space Learning. Weekly online one to one GCSE maths revision lessons delivered by expert maths tutors.

Find out more about our GCSE maths tuition programme.

You are watching: Pythagoras theorem. Info created by THVinhTuy selection and synthesis along with other related topics.

Rate this post