Answered: Directions: Find each missing length.…

7-2 Notes and HW
7-2 Notes and HW

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN: 9781133382119

Author: Swokowski

Publisher: Cengage

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I need help with knowing how to find missing side lengths and measures. Are any of these right if not what did I do wrong?

5. Name: Date: Bell: ** This is a 2-page document! ** Directions: Find each missing length. Give all answers in simplest radical form. 1. 2. 14+10²= 6² 16 18 196 +100 x=2√574 √580=1² 25k/5 C 2√10 y cos an 0 = 14 3. sin 0 = ■ y x 12 10 2x = 300 x 30 2 x=15 60° x = 2x y=15 y 7. Find the values of the six trigonometric functions for 0. 75 12² +5² = (² 5 144 +25=(² √169=C² 13 13 12 تر است 13 5 13 45° 90 √296122 2 UTO=x√2/2 y=2 x=2 csc 0 = sec 0 = cot 0 = 5 نادم Unit 12: Trigonometry Homework 1: Pythagorean Theorem, Special Right Triangles, & Trig Functions 18+16²=(² 324+256=530 14√3=x√3 √3 √5 X = H y=x√3 X 4. 6. 30° X 14√3 45° 16=x√3 16 x= 192 8. Find the values of the six trigonometric functions for 0. 16 2 12². ** = 16₂ 0 IN.XAj00 csc 0 = sec 0 w cot 0 = S 12 sin 0 = cos 0 = tan 0 => y 20 16 20 12 20 14 2 tor 20 16 20 12

Transcribed Image Text:5. Name: Date: Bell: ** This is a 2-page document! ** Directions: Find each missing length. Give all answers in simplest radical form. 1. 2. 14+10²= 6² 16 18 196 +100 x=2√574 √580=1² 25k/5 C 2√10 y cos an 0 = 14 3. sin 0 = ■ y x 12 10 2x = 300 x 30 2 x=15 60° x = 2x y=15 y 7. Find the values of the six trigonometric functions for 0. 75 12² +5² = (² 5 144 +25=(² √169=C² 13 13 12 تر است 13 5 13 45° 90 √296122 2 UTO=x√2/2 y=2 x=2 csc 0 = sec 0 = cot 0 = 5 نادم Unit 12: Trigonometry Homework 1: Pythagorean Theorem, Special Right Triangles, & Trig Functions 18+16²=(² 324+256=530 14√3=x√3 √3 √5 X = H y=x√3 X 4. 6. 30° X 14√3 45° 16=x√3 16 x= 192 8. Find the values of the six trigonometric functions for 0. 16 2 12². ** = 16₂ 0 IN.XAj00 csc 0 = sec 0 w cot 0 = S 12 sin 0 = cos 0 = tan 0 => y 20 16 20 12 20 14 2 tor 20 16 20 12

the nearest lanth. 12 9. Given the ratio for tan , find the remaining ratios. 25+14 √41 J CSC 8 = VIT 52 sec 8 = tan = cot 0 = 5 tan 0 = Directions: Give the exact ratios for each function below. 11. sin 45° 1 √2 12. tan 60° 15. sec 45° sin 8 = cos 8 = NIS 14. cot 60° SE 后 √3 Co+= 1 - اک √41 Vai 5 175 √2 10. Given the ratio for csc 0, find the remaining ratios. 7 2 51 sin = cos 0 = // NCHINI m/45 X 1 京 AVS J3 √3 3 Sec-3 SHyp csc = sec 0 = cot 0 = 13. cos 30° 16. csc 60° 17 /m/A/N 3/2 Ta اسکالر CSC AJ SHYP pate: Direc 1.

Transcribed Image Text:the nearest lanth. 12 9. Given the ratio for tan , find the remaining ratios. 25+14 √41 J CSC 8 = VIT 52 sec 8 = tan = cot 0 = 5 tan 0 = Directions: Give the exact ratios for each function below. 11. sin 45° 1 √2 12. tan 60° 15. sec 45° sin 8 = cos 8 = NIS 14. cot 60° SE 后 √3 Co+= 1 – اک √41 Vai 5 175 √2 10. Given the ratio for csc 0, find the remaining ratios. 7 2 51 sin = cos 0 = // NCHINI m/45 X 1 京 AVS J3 √3 3 Sec-3 SHyp csc = sec 0 = cot 0 = 13. cos 30° 16. csc 60° 17 /m/A/N 3/2 Ta اسکالر CSC AJ SHYP pate: Direc 1.

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